JEE PYQ: Area Under Curves Question 13
Question 13 - 2020 (03 Sep Shift 1)
The area (in sq. units) of the region ${(x, y) : 0 \leq y \leq x^2 + 1,\ 0 \leq y \leq x + 1,\ \frac{1}{2} \leq x \leq 2}$ is:
(1) $\frac{23}{16}$
(2) $\frac{79}{24}$
(3) $\frac{79}{16}$
(4) $\frac{23}{6}$
Show Answer
Answer: (2) $\frac{79}{24}$
Solution
Required area $= \int_{1/2}^{1}(x^2+1),dx + \int_1^2 (x+1),dx = \frac{79}{24}$.