JEE PYQ: Area Under Curves Question 16
Question 16 - 2020 (06 Sep Shift 2)
The area (in sq. units) of the region enclosed by the curves $y = x^2 - 1$ and $y = 1 - x^2$ is equal to:
(1) $\frac{4}{3}$
(2) $\frac{8}{3}$
(3) $\frac{7}{2}$
(4) $\frac{16}{3}$
Show Answer
Answer: (2) $\frac{8}{3}$
Solution
Area $= 4\int_0^1 (1-x^2),dx = \frac{8}{3}$.