JEE PYQ: Area Under Curves Question 21
Question 21 - 2019 (08 Apr Shift 1)
The area (in sq. units) of the region $A = {(x, y) \in \mathbb{R} \times \mathbb{R} | 0 \leq x \leq 3,\ 0 \leq y \leq 4,\ y \leq x^2 + 3x}$ is:
(1) $\frac{53}{6}$
(2) 8
(3) $\frac{59}{6}$
(4) $\frac{26}{3}$
Show Answer
Answer: (3) $\frac{59}{6}$
Solution
$y = x^2 + 3x$ meets $y = 4$ at $x = 1$. Area $= \int_0^1 (x^2+3x),dx + \int_1^3 4,dx = \frac{59}{6}$.
BETA
