JEE PYQ: Area Under Curves Question 23
Question 23 - 2019 (09 Apr Shift 1)
The area of the region $A = {(x, y) : x^2 \leq y \leq x + 2}$ is:
(1) $\frac{10}{3}$
(2) $\frac{9}{2}$
(3) $\frac{31}{6}$
(4) $\frac{13}{6}$
Show Answer
Answer: (2) $\frac{9}{2}$
Solution
$x^2 = x + 2 \Rightarrow x = -1, 2$. Area $= \int_{-1}^{2}(x+2-x^2),dx = \frac{9}{2}$.