JEE PYQ: Area Under Curves Question 24
Question 24 - 2019 (09 Apr Shift 2)
The area (in sq. units) of the region $A = \left{(x,y) : \frac{y^2}{2} \leq x \leq y + 4\right}$ is:
(1) $\frac{53}{3}$
(2) 30
(3) 16
(4) 18
Show Answer
Answer: (4) 18
Solution
$\frac{y^2}{2} = y + 4 \Rightarrow y = -2, 4$. Area $= \int_{-2}^{4}\left(y+4 - \frac{y^2}{2}\right)dy = 18$.