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If the area (in sq. units) bounded by the parabola $y^2 = 4\lambda x$ and the line $y = \lambda x$, $\lambda > 0$, is $\frac{1}{9}$, then $\lambda$ is equal to:
(1) $2\sqrt{6}$
(2) 48
(3) 24
(4) $4\sqrt{3}$
Area $= \frac{8}{3\lambda}$. $\frac{8}{3\lambda} = \frac{1}{9} \Rightarrow \lambda = 24$.
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