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The area (in sq. units) bounded by the parabola $y = x^2 - 1$, the tangent at the point $(2, 3)$ to it and the $y$-axis is:
(1) $\frac{8}{3}$
(2) $\frac{32}{3}$
(3) $\frac{56}{3}$
(4) $\frac{14}{3}$
Tangent: $y = 4x - 5$. Area $= 8 - \frac{16}{3} = \frac{8}{3}$.
BETA
