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If the area enclosed between the curves $y = kx^2$ and $x = ky^2$, $(k > 0)$, is 1 square unit. Then $k$ is:
(1) $\frac{\sqrt{3}}{2}$
(2) $\frac{1}{\sqrt{3}}$
(3) $\sqrt{3}$
(4) $\frac{2}{\sqrt{3}}$
Area $= \frac{1}{3k^2} = 1 \Rightarrow k = \frac{1}{\sqrt{3}}$.
BETA
