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The area (in sq. units) of the region bounded by the curve $x^2 = 4y$ and the straight line $x = 4y - 2$ is:
(1) $\frac{5}{4}$
(2) $\frac{9}{8}$
(3) $\frac{7}{8}$
(4) $\frac{3}{4}$
$x = -1, 2$. Area $= \frac{1}{4}\int_{-1}^{2}(x+2-x^2),dx = \frac{9}{8}$.
BETA
