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The area (in sq. units) of the region bounded by the parabola $y = x^2 + 2$ and the lines $y = x + 1$, $x = 0$ and $x = 3$, is:
(1) $\frac{15}{4}$
(2) $\frac{21}{2}$
(3) $\frac{17}{4}$
(4) $\frac{15}{2}$
Area $= \int_0^3 (x^2 - x + 1),dx = 9 - \frac{9}{2} + 3 = \frac{15}{2}$.
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