JEE PYQ: Binomial Theorem Question 11
Question 11 - 2021 (18 Mar Shift 2)
Let $P$ be a plane containing the line $\frac{x-1}{3} = \frac{y+6}{4} = \frac{z}{5}$ and parallel to the line $\frac{x-3}{4} = \frac{y-2}{-3} = \frac{z+5}{7}$. If the point $(1, -1, \alpha)$ lies on the plane $P$, then the value of $|5\alpha|$ is equal to ____.
Show Answer
Answer: 38
Solution
Normal to plane = cross product of direction vectors. After computing, $|5\alpha| = 38$.
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