JEE PYQ: Binomial Theorem Question 14
Question 14 - 2021 (24 Feb Shift 2)
${}^2C_2 = {}^3C_3$. $S = {}^3C_3 + {}^4C_3 + \ldots + {}^nC_3 = {}^{n+1}C_4$. The value of $\frac{n(n+1)(2n+1)}{6}$ is ____.
Show Answer
Answer: 12
Solution
Using hockey stick identity and solving, the answer is 12.