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JEE PYQ: Binomial Theorem Question 14

Question 14 - 2021 (24 Feb Shift 2)

${}^2C_2 = {}^3C_3$. $S = {}^3C_3 + {}^4C_3 + \ldots + {}^nC_3 = {}^{n+1}C_4$. The value of $\frac{n(n+1)(2n+1)}{6}$ is ____.

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Answer: 12

Solution

Using hockey stick identity and solving, the answer is 12.


Learning Progress: Step 14 of 55 in this series