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If the term independent of $x$ in the expansion of $\left(\frac{3}{2}x^2 - \frac{1}{3x}\right)^9$ is $k$, then $18k$ is equal to:
(1) 5 (2) 9 (3) 7 (4) 11
$r = 6$: $T_7 = 84 \cdot \frac{27}{8} \cdot \frac{1}{729} = \frac{7}{18}$. $18k = 7$.
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