JEE PYQ: Binomial Theorem Question 26
Question 26 - 2020 (05 Sep Shift 2)
The coefficient of $x^4$ in the expansion of $(1 + x + x^2 + x^3)^6$ in powers of $x$, is ____.
Show Answer
Answer: 120
Solution
$(1+x+x^2+x^3)^6 = \left(\frac{1-x^4}{1-x}\right)^6$. Coefficient of $x^4 = {}^9C_4 - 6 = 126 - 6 = 120$.