JEE PYQ: Binomial Theorem Question 28
Question 28 - 2020 (06 Sep Shift 2)
If the constant term in the binomial expansion of $\left(\sqrt{x} - \frac{k}{x^2}\right)^{10}$ is 405, then $|k|$ equals:
(1) 9 (2) 1 (3) 3 (4) 2
Show Answer
Answer: (3)
Solution
$r = 2$: ${}^{10}C_2 k^2 = 405$, $k^2 = 9$, $|k| = 3$.