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If the coefficients of $x^2$ and $x^3$ are both zero, in the expansion of $(1 + ax + bx^2)(1-3x)^{15}$, then $(a, b)$ is equal to:
(1) $(28, 861)$ (2) $(-54, 315)$ (3) $(28, 315)$ (4) $(-21, 714)$
Solving the system: $a = 28, b = 315$.
BETA
