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JEE PYQ: Binomial Theorem Question 41

Question 41 - 2019 (10 Apr Shift 2)

The smallest natural number $n$, such that the coefficient of $x$ in the expansion of $\left(x^2 + \frac{1}{x^3}\right)^n$ is ${}^nC_{23}$, is:

(1) 38 (2) 58 (3) 23 (4) 35

Show Answer

Answer: (1)

Solution

$2n - 5r = 1$ with ${}^nC_r = {}^nC_{23}$. If $n - r = 23$: $n = 38$. Smallest is 38.


Learning Progress: Step 41 of 55 in this series