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If the fractional part of the number $\frac{2^{403}}{15}$ is $\frac{k}{15}$, then $k$ is equal to:
(1) 6 (2) 8 (3) 4 (4) 14
$2^{403} = 8(1+15)^{100} = 8 + 8 \cdot 15\mu$. Fractional part $= 8/15$, $k = 8$.
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