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If the third term in the binomial expansion of $\left(1 + x^{\log_2 x}\right)^5$ equals 2560, then a possible value of $x$ is:
(1) $\frac{1}{4}$ (2) $4\sqrt{2}$ (3) $\frac{1}{8}$ (4) $2\sqrt{2}$
$(\log_2 x)^2 = 4$, $x = 4$ or $x = 1/4$.
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