JEE PYQ: Binomial Theorem Question 49
Question 49 - 2019 (10 Jan Shift 2)
The positive value of $\lambda$ for which the co-efficient of $x^2$ in the expression $x^2\left(\sqrt{x} + \frac{\lambda}{x^2}\right)^{10}$ is 720, is:
(1) 4 (2) $2\sqrt{2}$ (3) $\sqrt{5}$ (4) 3
Show Answer
Answer: (1)
Solution
$r = 2$: $45\lambda^2 = 720$, $\lambda = 4$.