JEE PYQ: Binomial Theorem Question 54
Question 54 - 2019 (11 Jan Shift 2)
Let $(x + 10)^{50} + (x - 10)^{50} = a_0 + a_1 x + a_2 x^2 + \ldots + a_{50} x^{50}$, for all $x \in \mathbb{R}$; then $\frac{a_2}{a_0}$ is equal to:
(1) 12.50 (2) 12.00 (3) 12.25 (4) 12.75
Show Answer
Answer: (3)
Solution
$\frac{a_2}{a_0} = \frac{{}^{50}C_2}{100} = \frac{1225}{100} = 12.25$.