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The ratio of the 5th term from the beginning to the 5th term from the end in the binomial expansion of $\left(2^{1/3} + \frac{1}{2(3)^{1/3}}\right)^{10}$ is:
(1) $1 : 2(6)^{1/3}$ (2) $1 : 4(16)^{1/3}$ (3) $4(36)^{1/3} : 1$ (4) $2(36)^{1/3} : 1$
$T_5/T_7 = 4(36)^{1/3}$.
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