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The minimum distance between any two points $P_1$ and $P_2$ while considering point $P_1$ on one circle and point $P_2$ on the other circle for the given circles’ equations
$x^2 + y^2 - 10x - 10y + 41 = 0$
$x^2 + y^2 - 24x - 10y + 160 = 0$ is ______.
$C_1(5,5), r_1 = 3$; $C_2(12,5), r_2 = 3$. $C_1C_2 = 7 > r_1 + r_2 = 6$. Minimum distance $= 7 - 6 = 1$.
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