JEE PYQ: Circle Question 8
Question 8 - 2021 (18 Mar Shift 1)
For the four circles $M, N, O$ and $P$, following four equations are given:
Circle $M: x^2 + y^2 = 1$ Circle $N: x^2 + y^2 - 2x = 0$ Circle $O: x^2 + y^2 - 2x - 2y + 1 = 0$ Circle $P: x^2 + y^2 - 2y = 0$
If the centre of circle $M$ is joined with centre of circle $N$, further centre of circle $N$ is joined with centre of circle $O$, centre of circle $O$ is joined with centre of circle $P$ and lastly, centre of circle $P$ is joined with centre of circle $M$, then these lines form the sides of a:
(1) Rhombus
(2) Square
(3) Rectangle
(4) Parallelogram
Show Answer
Answer: (2)
Solution
Centers: $M(0,0)$, $N(1,0)$, $O(1,1)$, $P(0,1)$. These form a square with side 1.
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