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JEE PYQ: Continuity And Differentiability Question 13

Question 13 - 2020 (04 Sep Shift 2)

The function $f(x) = \begin{cases} \dfrac{\pi}{4} + \tan^{-1}x, & |x| \leq 1 \ \dfrac{1}{2}(|x| - 1), & |x| > 1 \end{cases}$ is:

(1) continuous on $\mathbb{R} - {1}$ and differentiable on $\mathbb{R} - {-1, 1}$

(2) both continuous and differentiable on $\mathbb{R} - {1}$

(3) continuous on $\mathbb{R} - {-1}$ and differentiable on $\mathbb{R} - {-1, 1}$

(4) both continuous and differentiable on $\mathbb{R} - {-1}$

Show Answer

Answer: (1)


Learning Progress: Step 13 of 36 in this series