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JEE PYQ: Continuity And Differentiability Question 14

Question 14 - 2020 (05 Sep Shift 1)

If the function $f(x) = \begin{cases} k_1(x - \pi)^2 - 1, & x \leq \pi \ k_2 \cos x, & x > \pi \end{cases}$ is twice differentiable, then the ordered pair $(k_1, k_2)$ is equal to:

(1) $\left(\dfrac{1}{2}, 1\right)$

(2) $(1, 0)$

(3) $\left(\dfrac{1}{2}, -1\right)$

(4) $(1, 1)$

Show Answer

Answer: (1)


Learning Progress: Step 14 of 36 in this series