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If the function $f$ defined on $\left(-\dfrac{1}{3}, \dfrac{1}{3}\right)$ by
$$f(x) = \begin{cases} \dfrac{1}{x} \log_e\left(\dfrac{1 + 3x}{1 - 2x}\right), & \text{when } x \neq 0 \ k, & \text{when } x = 0 \end{cases}$$
is continuous, then $k$ is equal to ______.
BETA
