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The integral $\int_{\pi/6}^{\pi/3} \tan^3 x \cdot \sin^2 3x(2\sec^2 x \cdot \sin^2 3x + 3\tan x \cdot \sin 6x),dx$ is equal to:
(1) $\dfrac{7}{18}$
(2) $-\dfrac{1}{9}$
(3) $-\dfrac{1}{18}$
(4) $\dfrac{9}{2}$
BETA
