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Consider the integral $I = \int_0^{10} \dfrac{[x]e^{[x]}}{e^{x-1}},dx$
where $[x]$ denotes the greatest integer less than or equal to $x$. Then the value of $I$ is equal to:
(1) $9(e - 1)$
(2) $45(e + 1)$
(3) $45(e - 1)$
(4) $9(e + 1)$
BETA
