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If $I = \int_1^2 \dfrac{dx}{\sqrt{2x^3 - 9x^2 + 12x + 4}}$, then:
(1) $\dfrac{1}{8} < I^2 < \dfrac{1}{4}$
(2) $\dfrac{1}{9} < I^2 < \dfrac{1}{8}$
(3) $\dfrac{1}{16} < I^2 < \dfrac{1}{9}$
(4) $\dfrac{1}{6} < I^2 < \dfrac{1}{2}$
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