JEE PYQ: Definite Integration Question 47
Question 47 - 2019 (10 Jan Shift 2)
If $\int_0^{\pi/3} \dfrac{\tan\theta}{\sqrt{2k\sec\theta}},d\theta = 1 - \dfrac{1}{\sqrt{2}}$, $(k > 0)$ then the value of $k$ is:
(1) $4$
(2) $\dfrac{1}{2}$
(3) $1$
(4) $2$