JEE PYQ: Differentiation Question 18
Question 18 - 2019 (10 Jan Shift 1)
Let $f : \mathbb{R} \to \mathbb{R}$ be a function such that $f(x) = x^3 + x^2f’(1) + xf’’(2) + f’’’(3)$, $x \in \mathbb{R}$. Then $f(2)$ equals:
(1) $-4$ (2) $30$ (3) $-2$ (4) $8$
Show Answer
Answer: (3) $-2$
Solution
$f(x) = x^3 - 5x^2 + 2x + 6$. $f(2) = 8 - 20 + 4 + 6 = -2$.