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If the co-ordinates of two points A and B are $(\sqrt{7}, 0)$ and $(-\sqrt{7}, 0)$ respectively and P is any point on the conic, $9x^2 + 16y^2 = 144$, then PA + PB is equal to:
(a) 16 (b) 8 (c) 6 (d) 9
Ellipse: $\frac{x^2}{16} + \frac{y^2}{9} = 1$
$a = 4$, $b = 3$, $c = \sqrt{7}$
$(\pm\sqrt{7}, 0)$ are the foci. $PA + PB = 2a = 8$
BETA
