JEE PYQ: Functions Question 32
Question 32 - 2019 (09 Jan Shift 1)
For $x \in \mathbb{R} - {0, 1}$, let $f_1(x) = \frac{1}{x}$, $f_2(x) = 1-x$ and $f_3(x) = \frac{1}{1-x}$. If a function, $J(x)$ satisfies $(f_2 \circ J \circ f_1)(x) = f_3(x)$ then $J(x)$ is equal to:
(1) $f_3(x)$
(2) $\frac{1}{x} f_3(x)$
(3) $f_2(x)$
(4) $f_1(x)$
Type: MCQ
Show Answer
Answer: (1) $f_3(x)$
Solution
$J(x) = 1 - \frac{x}{x-1} = \frac{1}{1-x} = f_3(x)$