JEE PYQ: Functions Question 36
Question 36 - 2019 (11 Jan Shift 1)
Let $f : \mathbb{R} \to \mathbb{R}$ be defined by $f(x) = \frac{x}{1+x^2}$, $x \in \mathbb{R}$. Then the range of $f$ is:
(1) $\left[-\frac{1}{2}, \frac{1}{2}\right]$
(2) $\mathbb{R} - [-1, 1]$
(3) $\mathbb{R} - \left[-\frac{1}{2}, \frac{1}{2}\right]$
(4) $(-1, 1) - {0}$
Type: MCQ
Show Answer
Answer: (1) $\left[-\frac{1}{2}, \frac{1}{2}\right]$
Solution
$|y| \le \frac{1}{2}$, range is $\left[-\frac{1}{2}, \frac{1}{2}\right]$
BETA
