JEE PYQ: Heights And Distances Question 1
Question 1 - 2021 (18 Mar Shift 2)
A pole stands vertically inside a triangular park $ABC$. Let the angle of elevation of the top of the pole from each corner of the park be $\frac{\pi}{3}$. If the radius of the circumcircle of $\triangle ABC$ is 2, then the height of the pole is equal to:
(1) $\frac{2\sqrt{3}}{3}$ (2) $2\sqrt{3}$ (3) $\sqrt{3}$ (4) $\frac{1}{\sqrt{3}}$
Show Answer
Answer: (2) $2\sqrt{3}$
Solution
Pole is at circumcentre. $h = R\tan\frac{\pi}{3} = 2\sqrt{3}$.
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