JEE PYQ: Heights And Distances Question 6
Question 6 - 2020 (04 Sep Shift 2)
The angle of elevation of a cloud $C$ from a point $P$, 200 m above a still lake is $30°$. If the angle of depression of the image of $C$ in the lake from the point $P$ is $60°$, then $PC$ (in m) is equal to:
(1) $100$ (2) $200\sqrt{3}$ (3) $400$ (4) $400\sqrt{3}$
Show Answer
Answer: (3) $400$
Solution
$\frac{h+200}{h-200} = 3 \Rightarrow h = 400$. $PC = \frac{200}{\sin 30°} = 400$ m.
BETA
