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Let AD and BC be two vertical poles at A and B respectively on a horizontal ground. If $AD = 8$ m, $BC = 11$ m and $AB = 10$ m, then the distance (in meters) of a point M on AB from the point A such that $MD^2 + MC^2$ is minimum is ____.
$f(x) = 64 + x^2 + 121 + (10-x)^2$. $f’(x) = 0 \Rightarrow x = 5$.
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