JEE PYQ: Limits Question 17
Question 17 - 2020 (06 Sep Shift 1)
$\lim_{x \to 1} \left(\frac{\int_0^{(x-1)^2} t\cos(t^2),dt}{(x-1)\sin(x-1)}\right)$ is:
(1) is equal to $\frac{1}{2}$
(2) is equal to $0$
(3) is equal to $-\frac{1}{2}$
(4) does not exist
Show Answer
Answer: (2)
Solution
Let $x - 1 = h$. $\lim_{h\to 0}\frac{\frac{1}{2}\sin(h^4)}{h^2} \times \frac{h}{\sin h} = \lim_{h\to 0}\frac{\sin(h^4)}{2h^2} = 1 \times 1 \times 0 = 0$.