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$\lim_{x \to 0} \frac{\int_0^x t\sin(10t),dt}{x}$ is equal to:
(1) $0$
(2) $\frac{1}{10}$
(3) $-\frac{1}{5}$
(4) $-\frac{1}{10}$
Using L’Hospital rule: $\lim_{x\to 0}\frac{x\sin(10x)}{1} = 0$.
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