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If $\lim_{x \to 1} \frac{x^2 - ax + b}{x - 1} = 5$, then $a + b$ is equal to:
(1) $-4$
(2) $5$
(3) $-7$
(4) $1$
For limit to be finite, $1 - a + b = 0$. Then $\lim_{x\to 1}\frac{2x - a}{1} = 5 \Rightarrow 2 - a = 5 \Rightarrow a = -3$ and $b = -4$. So $a + b = -3 - 4 = -7$.
BETA
