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The logical statement $(p \Rightarrow q) \wedge (q \Rightarrow \sim p)$ is equivalent to:
(1) $p$
(2) $q$
(3) $\sim p$
(4) $\sim q$
Type: MCQ
Clearly $(p \Rightarrow q) \wedge (q \Rightarrow \sim p)$ is equivalent to $\sim p$.
BETA
