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If the system of linear equations $x + y + 3z = 0$, $x + 3y + k^2 z = 0$, $3x + y + 3z = 0$ has a non-zero solution $(x, y, z)$ for some $k \in \mathbb{R}$, then $x + \left(\dfrac{y}{z}\right)$ is equal to:
(1) $-3$
(2) $9$
(3) $3$
(4) $-9$
BETA
