JEE PYQ: Matrices And Determinants Question 6
Question 6 - 2021 (17 Mar Shift 1)
The system of equations $kx + y + z = 1$, $x + ky + z = k$ and $x + y + zk = k^2$ has no solution if $k$ is equal to:
(1) $0$
(2) $1$
(3) $-1$
(4) $-2$
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The system of equations $kx + y + z = 1$, $x + ky + z = k$ and $x + y + zk = k^2$ has no solution if $k$ is equal to:
(1) $0$
(2) $1$
(3) $-1$
(4) $-2$