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If the system of linear equations $x - 2y + kz = 1$, $2x + y + z = 2$, $3x - y - kz = 3$ has a solution $(x, y, z)$, $z \neq 0$, then $(x, y)$ lies on the straight line whose equation is:
(1) $3x - 4y - 1 = 0$
(2) $4x - 3y - 4 = 0$
(3) $4x - 3y - 1 = 0$
(4) $3x - 4y - 4 = 0$
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