JEE PYQ: Matrices And Determinants Question 84
Question 84 - 2019 (11 Jan Shift 2)
$\begin{vmatrix} a - b - c & 2a & 2a \ 2b & b - c - a & 2b \ 2c & 2c & c - a - b \end{vmatrix} = (a + b + c)(x + a + b + c)^2$, $x \neq 0$ and $a + b + c \neq 0$, then $x$ is equal to:
(1) $abc$
(2) $-(a + b + c)$
(3) $2(a + b + c)$
(4) $-2(a + b + c)$