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Let $A$ and $B$ be two invertible matrices of order $3 \times 3$. If $\det(ABA^T) = 8$ and $\det(AB^{-1}) = 8$, then $\det(BA^{-1}B^T)$ is equal to:
(1) $\dfrac{1}{4}$
(2) $1$
(3) $\dfrac{1}{16}$
(4) $16$
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