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If the sides AB, BC and CA of a triangle ABC have 3, 5 and 6 interior points respectively, then the total number of triangles that can be constructed using these points as vertices, is equal to:
(1) 364
(2) 240
(3) 333
(4) 360
Total triangles $= {}^{14}C_3 - {}^3C_3 - {}^5C_3 - {}^6C_3 = 364 - 1 - 10 - 20 = 333$.
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