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The integer ‘$k$’, for which the inequality $x^2 - 2(3k - 1)x + 8k^2 - 7 > 0$ is valid for every $x$ in $R$ is:
(1) 3
(2) 2
(3) 4
(4) 0
$D < 0$
$(2(3k-1))^2 - 4(8k^2 - 7) < 0$
$4(9k^2 - 6k + 1) - 4(8k^2 - 7) < 0$
$k^2 - 6k + 8 < 0$
$(k - 4)(k - 2) < 0$
$2 < k < 4$
then $k = 3$
BETA
