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JEE PYQ: Sequence And Series Question 22

Question 22 - 2020 (03 Sep Shift 1)

If the first term of an A.P. is 3 and the sum of its first 25 terms is equal to the sum of its next 15 terms, then the common difference of this A.P. is:

(1) $\frac{1}{6}$

(2) $\frac{1}{5}$

(3) $\frac{1}{4}$

(4) $\frac{1}{7}$

Show Answer

Answer: (1)

Solution

Given $a = 3$ and $S_{25} = S_{40} - S_{25}$

$\Rightarrow 2S_{25} = S_{40}$

$\Rightarrow 2 \times \frac{25}{2}[6 + 24d] = \frac{40}{2}[6 + 39d]$

$\Rightarrow 25(6 + 24d) = 20(6 + 39d)$

$\Rightarrow 5(2 + 8d) = 4(2 + 13d)$

$\Rightarrow 10 + 40d = 8 + 52d$

$\Rightarrow d = \frac{1}{6}$


Learning Progress: Step 22 of 70 in this series